How to set 1d array to 2d array element in C -
i need this: char font[128][8] = {{0}}; font[0][] = {0, 0b00000000, 0b11111100, 0b00010010, 0b00010010, 0b11111100, 0b00000000, 0}; font[1][] = {...} but in c99 "expected expression before '{' token". please help. you can use initialiser list ( {...} ) when declaring array, that's why you're getting error. can't assign value array, font[0] (a char[] ). you have 3 options: char font[128][8] = { {0, 0b00000000, 0b11111100, 0b00010010, 0b00010010, 0b11111100, 0b00000000, 0}; {...} } assign each value element in array individually: font[0][0] = x , ..., font[127][7] = y (ie. using loop). memcpy blocks @ time uint64_t ( sizeof(font[0]) = 8 ) or wherever else can neatly/efficiently store data. it's worth noting binary constants c extension, and char signed , if you're working unsigned data should explicitly use unsigned char .
