stdvector - Copy from vector<pointer*> to vector<pointer*> in C++ -

i create vector , want copy vector b in class using below method, correct way? vector may destroyed! searched in google, not found solution , meaningful explanation. everyone

void  stateinit(vector<cbutton*> listbtn)  {     _m_plistbtn = listbtn;   }; 

yes , no, passing vector value:

void  stateinit(vector<cbutton*> listbtn)  {     _m_plistbtn = listbtn;   }; 

wich means listbtn copy of vector (asuming calling vector 1 passed parameter of stateinit), if delete vector a, vector b still have collection of pointers , valid since destruction of vector of pointers doesnt delete pointed objects because cant possible how (should call, delete, delete[], free?).

do keep in mind if modify/delete 1 of elements vector (using pointers on vector), element modified in vector b (since pointer same element).

im not sure intend this, if want copy whole vector, should implement clone mechanism objects , copy them using transform:

class clonefunctor { public:     t* operator() (t* a) {         return a->clone();     } } 

then just:

void  stateinit(vector<cbutton*> listbtn)  {     transform(listbtn.begin(), listbtn.end(), back_inserter(_m_plistbtn), clonefunctor());   }; 

if intention not clone share pointers should pass vector pointer or reference:

void stateinit(const vector<cbutton*>& listbtn)  {     _m_plistbtn = listbtn;  };