Strange Behavior in final variable in Java -

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• how “final int i” work inside of java loop? 2 answers

in java program have used 1 final variable.we know value of final variable fixed , can't changed.so why particular program working fine?can explain.

public static void main(string args[]) {     int[] integerarray = { 1, 2, 3, 4, 5 };      (final int j : integerarray) {     system.out.println(j);     } } 

it's final within body of loop - you're declaring different variable each iteration of loop.

it's if you'd written this:

for (int = 0; < integerarray.length; i++) {     final int j = integerarray[i];     system.out.println(j); } 

again, have "new" local variable called j on each iteration of loop... each of variables never changes value.