Fragment android:visibility in xml layout definition -

how works? have layout below:

<linearlayout     android:layout_width="match_parent"     android:layout_height="match_parent"     android:orientation="vertical" >      <fragment         android:id="@+id/search_form_fragment"         android:name="fragmentclass"         android:layout_width="match_parent"         android:layout_height="match_parent" />      <fragment         android:id="@+id/result_list_fragment"         android:name="fragmentclass"         android:layout_width="match_parent"         android:layout_height="match_parent"         android:visibility="gone" /> </linearlayout> 

note second fragment has android:visibility="gone" , indeed not visible on screen. code:

boolean bothvisible = firstfrag.isvisible() && secondfrag.isvisible(); 

returns true, not expected me. wonder if using android:visibility correct cause not find information in documentation.

per fragment source, isvisible defined as:

 final public boolean isvisible() {     return isadded() && !ishidden() && mview != null             && mview.getwindowtoken() != null &&                 mview.getvisibility() == view.visible; } 

i.e., attached activity, not hidden (via fragmenttransaction.hide), view inflated, view attached window, , interior view of fragment view.visible.

i believe issue in order inflate fragment, system creates layout hold fragment's view. view setting view.gone, not interior view fragment creates.

i might suggest changing condition be:

findviewbyid(r.id.result_list_fragment).getvisibility() == view.visible