pointers - Error at "cout << " in C++ -

i trying reverse char array in c++. here code :

void reverse(char s[]); int main() {     char s [] = "harry";     cout << reverse(s) << endl;      system("pause");     return 0; }  void reverse(char s[]) {     if( strlen( s ) > 0 ) {         char* first = &s[ 0 ];         char* last = &s[ strlen( s ) - 1 ];         while( first < last ) {             char tmp = *first;             *first = *last;             *last = tmp;             ++first;             --last;         }         return;     } 

however, got error @ cout << reverse(s) << endl; line located in main method , have no idea why.the error message no operator match these operands. can me fix this?

thanks in advance.

your reverse function has return type of void. means doesn't return cout << reverse() has nothing output.

seems instead meant do:

char s [] = "harry"; reverse(s); cout << s << endl; 

alternatively, can make reverse return char* , put return s; @ end of body. however, little strange, since you're using both argument , return value same function output. use above.

of course, more if make use of standard library; use std::string , std::reverse:

std::string s = "test"; std::reverse(s.begin(), s.end()); std::cout << s << std::endl; 

see in action.