php - Complex SQL query JOIN and WHERE -


i have table, need contacts from. use complex query retrieve contacts "sms" table.

however, should count records provided "imei" field, query keeps returning counts specific contact.

below code use, advice?

$sql = $this->db->query('     select          t1.mnumber t1_number, t1.mcontent t1_content, t1.mcontact t1_contact, sum(t2.total) mtotal             sms t1             join         (select              mcontent, mcontact, count(mnumber) total, mnumber, max(mid) mid                     sms         group mcontact) t2 on t1.mcontact = t2.mcontact             , t1.mid = t2.mid         t1.mimei = ' . (imei) . '         group t1.mcontact         order t1.mid desc');      return $sql->result(); 

thanks you!!

better formatted, query is:

select t1.mnumber t1_number, t1.mcontent t1_content, t1.mcontact t1_contact, sum(t2.total) mtotal sms t1 join      (select mcontent, mcontact, count(mnumber) total, mnumber, max(mid) mid       sms       group mcontact      ) t2      on t1.mcontact = t2.mcontact , t1.mid = t2.mid t1.mimei = ' . (imei) . ' group t1.mcontact order t1.mid desc 

the problem where clause in wrong place. affect count, need in subquery. affect output rows, need in outer query. suggest:

select t1.mnumber t1_number, t1.mcontent t1_content, t1.mcontact t1_contact, sum(t2.total) mtotal sms t1 join      (select mcontent, mcontact, count(mnumber) total, mnumber, max(mid) maxmid       sms       sms.mimei = ' . (imei) . '       group mcontact      ) t2      on t1.mcontact = t2.mcontact , t1.mid = t2.maxmid group t1.mcontact order t1.mid desc 

i suspect there may other simplifications, depending on mid andmcontact mean in terms of database structure.


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