python - printing a string with function calls -
i have ast.dump so:
"module(body=[assign(targets=[name(id='i', ctx=store())], value=num(n=0)), while(test=compare(left=name(id='i', ctx=load()), ops=[lt()], comparators=[num(n=10)]), body=[print(dest=none, values=[name(id='i', ctx=load())], nl=true), augassign(target=name(id='i', ctx=store()), op=add(), value=num(n=1))], orelse=[]), for(target=name(id='x', ctx=store()), iter=call(func=name(id='range', ctx=load()), args=[num(n=10)], keywords=[], starargs=none, kwargs=none), body=[print(dest=none, values=[name(id='x', ctx=load())], nl=true)], orelse=[])])" how (pretty) print in more readable form 1 below??
module( body=[assign(targets=[name(id='i', ctx=store())], value=num(n=0)), while(test=compare(left=name(id='i', ctx=load()), ops=[lt()], comparators=[num(n=10)]), body=[print(dest=none, values=[name(id='i', ctx=load())], nl=true), augassign(target=name(id='i', ctx=store()), op=add(), value=num(n=1))], orelse=[]), for(target=name(id='x', ctx=store()), iter=call(func=name(id='range', ctx=load()), args=[num(n=10)], keywords=[], starargs=none, kwargs=none), body=[print(dest=none, values=[name(id='x', ctx=load())], nl=true)], orelse=[])]) incase wondering code generated this:
text = ''' = 0 while < 10: print += 1 x in range(10): print x ''' ast.dump(ast.parse(text))
it's done, example by function or astpp module.
the latter 1 code:
import ast import astpp tree = ast.parse( """ print "hello world!" s = "i'm string!" print s """) print astpp.dump(tree) should produce output:
module(body=[ print(dest=none, values=[ str(s='hello world!'), ], nl=true), assign(targets=[ name(id='s', ctx=store()), ], value=str(s="i'm string!")), print(dest=none, values=[ name(id='s', ctx=load()), ], nl=true), ]) 
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