PHP if statement. Display and image if true -

i'm accessing api returning value of array. want image displayed based on result. example if div contains "above average" display image called aboveaverage.png.

echo $cinfo['crimes']['2013-03']['anti-social-behaviour']['crime_level']; 

this results "above average" how can display particular image correspond this?

something ->

if div "crime_level" = above average then: display aboveaverage.png 

i'm pretty new php, sorry i'm noob.

use case selecting switch

switch ($cinfo['crimes']['2013-03']['anti-social-behaviour']['crime_level']) {               case "above average":                 $image = "aboveaverage.png";             break;             case "below average":                 $image = "belowaverage.png";             break;             default:                 $image = "unknown.png";             };  echo "<img src=\"$image\" />"; 

doing way allows remove logic display setting variable $image you're not having update 20 different potential image tags. allows cater many different cases of string without ending lost in if else hell