PHP if statement. Display and image if true -
i'm accessing api returning value of array. want image displayed based on result. example if div contains "above average" display image called aboveaverage.png.
echo $cinfo['crimes']['2013-03']['anti-social-behaviour']['crime_level'];
this results "above average" how can display particular image correspond this?
something ->
if div "crime_level" = above average then: display aboveaverage.png
i'm pretty new php, sorry i'm noob.
use case selecting switch
switch ($cinfo['crimes']['2013-03']['anti-social-behaviour']['crime_level']) { case "above average": $image = "aboveaverage.png"; break; case "below average": $image = "belowaverage.png"; break; default: $image = "unknown.png"; }; echo "<img src=\"$image\" />";
doing way allows remove logic display setting variable $image you're not having update 20 different potential image tags. allows cater many different cases of string without ending lost in if else hell
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