linux - C write() function sending 2 bytes hexadecimal -

i'm working tcp sockets. i'm sending data open socket using write function.

write(socket_fd, "test", 4);

that works. when way.

#include <stdio.h> #include <stdlib.h>  typedef unsigned char byte;  typedef struct lanc {  byte start;  byte end;  } lcode;   int main(int argc, char *argv[]){  lcode command; command.start = 0x28; command.end = 0x06;  short value = (command.start << 8) | command.end;  write(socket_fd, value, sizeof(value);  return 0; } 

when check size of value 2 bytes correct since combined 0x28 , 0x06. doing printf.

printf("%x\n", value);  output is: 2806 correct.  printf("%d\n", sizeof(value);  output is: 2 bytes correct. 

i'm getting error when i'm trying write hexadecimal open socket using write. doing wrong?

you're committing 2 disgusting errors in 1 line (how compile?). you're passing integer (value) write() expects pointer (that won't compile, you're trying deceive code). secondly, you're doing that's endian-dependant, is, on different processors you'll different results depending on whether high-byte of "value" comes first or second in memory.

solution:

unsigned char value[2] = {command.start, command.end};  write(socket_fd, value, sizeof(value));