c - Looping through string - exit on null not zero -

i've written small program highlight problem i'm having in c. expected in following code, display loop print 0, exit on null; however, loop exits on 0. on earth missing / don't understand? appreciated.

#include <stdio.h>  int main (void) {     int = 0;     int iarray[] = {1, 2, 0, 4, 5, '\0'};     int carray[] = {1, 2, 0, 4, 5, '\0'};      for(i=0; iarray[i] != '\0'; i++)     {         printf("\nelement: %d", iarray[i]);     }      for(i=0; carray[i] != '\0'; i++)     {         printf("\nelement: %d", iarray[i]);     }     return 0; } 

thanks, dan

you're missing quotes, seem want create string of digits. digit '1' not same character value 1.

also, arrays mysteriously int, when should char.

try:

const char iarray[] = { '1', '2', '0', '4', '5', '\0'}; 

which of course can simpler written as:

const char iarray[] = "12045";