c++ - How to get boost multiprecision number parts? -

say have number:

// bmp = boost::multiprecision bmp::cpp_dec_float n("123456789.1234567891011121314"); 

its backend data are:

[0]  1         unsigned int [1]  23456789  unsigned int [2]  12345678  unsigned int [3]  91011121  unsigned int [4]  31400000  unsigned int ...  0 [15] 0         unsigned int 

which want get; unfortunately, don't find way either both parts of number bmp::int128_t --for instance--, or underlying data of number.

that is, exists:

bmp::int128_t integerpart; bmp::int128_t floatpart; n.getparts(integerpart, floatpart); 

or

auto&& data = n.data(); // private when using `cpp_dec_float`. 

anyway, known how trying achieve?

for record, need express big decimal number c# decimal sake of interoperability.

from boost documentation end intentionally opaque may change @ time without warning. (class template cpp_dec_float fulfils of requirements backend type. members , non-member functions deliberately not documented: these considered implementation details subject change.) http://www.boost.org/doc/libs/1_55_0/libs/multiprecision/doc/html/boost_multiprecision/ref/cpp_dec_ref.html

as far can see have 2 choices here. can @ source code specific version of backend class you're using, access number using backend method, , hope backend never changes (especially consider changes broke binary format , not compilation).

alternately recommend take string representation of cpp_dec_float , split 2 parts yourself, using string or char* constructors underlying integral types you're interested in.