Scala: How to call trim on every element of a Tuple -

i need write function takes tuple of string of size, call trims on each element , returns new tuple. kind of stuck @ point below , code not type safe. in addition not know how go tuple once convert iterator. there more elegant way solve problem? solutions needs work on scala 2.9.2

  def trim(input:product)={     input.productiterator.asinstanceof[iterator[string]].map(_.trim)   } 

if you're willing go solution uses shapeless, pretty straightforward (in shapeless terms, @ least):

import shapeless._  object trimmer extends (string -> string)(_.trim)  def trim[t <: product, l <: hlist](t: t)(implicit   hlister: hlisteraux[t, l],   tolist: tolist[l, string],   mapper: mapperaux[trimmer.type, l, l],   tupler: tupleraux[l, t] ) = hlister(t).map(trimmer).tupled 

and then:

scala> trim((" ", "b ", " c")) res0: (string, string, string) = (a,b,c)  scala> trim((" ", "b ", " c", "d")) res1: (string, string, string, string) = (a,b,c,d) 

everything's statically typed appropriately, , if try feed tuple non-string elements, you'll error @ compile time.

without library shapeless—which packages boilerplate you—you're stuck 2 options: give type safety, or write special case every tuple size care (up maximum of 22).