C++ Pointer Pointing to index of an Array of Objects -


quick questions pointers. in example:

  object *o;    object** array = new object*[3];    o = array[0];

in example, o point spot array[0] or object located in position? example, if object in index 0 gets swapped object in spot 2, understand o should still have access object not new 1 in array[0], right?

sorry want double check. been working on day w/o sleep & starting question what's @ point.

your assumptions correct.

when doing o = array[0]; assignment (which equivalent writing o = (*array);) copy pointer stored in array pointer variable o. change array afterwards won't change contents of o, since copy.


Comments

Post a Comment

Popular posts from this blog

Java sticky instances of class com.mysql.jdbc.Field aggregating -

i noticed (via jmap+jhat) app leaking storing many instances com.mysql.jdbc.field  class - double checked code make sure closing preparedstatements, find few missing didn't change outcome. - preparedstatement created , closed right away - several others created @ start , reused many times - using org.apache.tomcat.jdbc.pool.datasource connection pool what can cause type of behavior? are closing of preparedstatements / result sets using: preparedstatement stmt (possible assignment here); try { // work prepared statement resultset rs; try { while (rs.next()) ... // process results } { rs.close(); } } { stmt.close(); } so guarantee result sets closed when finished (regardless of exceptions) , statements closed (regardless of exceptions)? there other ways write that, idea same. if you're doing of properly, unless have many references it's taking inordinate amount of memory, it's ok , nothing needs done it.
Read more